MHT CET · Maths · Indefinite Integration
\(\int \frac{\mathrm{d} x}{2+\cos x}=\) (Where \(C\) is a constant of integration.)
- A \(\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{\tan \left(\frac{x}{2}\right)}{2 \sqrt{3}}\right)+C\)
- B \(\frac{1}{2 \sqrt{3}} \tan ^{-1}\left(\frac{\tan \left(\frac{x}{2}\right)}{2 \sqrt{3}}\right)+C\)
- C \(\frac{1}{\sqrt{3}} \tan ^{-1}\left(\frac{\tan \left(\frac{x}{2}\right)}{\sqrt{3}}\right)+C\)
- D \(\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{\tan \left(\frac{x}{2}\right)}{\sqrt{3}}\right)+C\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{\tan \left(\frac{x}{2}\right)}{\sqrt{3}}\right)+C\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \int \frac{\mathrm{d} x}{2+\cos x}=\int \frac{\mathrm{d} x}{2+\frac{1-\tan ^2 \frac{x}{2}}{1+\tan ^2 \frac{x}{2}}}=\int \frac{\sec ^2 \frac{x}{2} \mathrm{~d} x}{3+\tan ^2 \frac{x}{2}} \\ & =2 \int \frac{\frac{1}{2} \sec ^2 \frac{x}{2} \mathrm{~d} x}{(\sqrt{3})^2+\left(\tan \frac{x}{2}\right)^2}=\frac{2}{\sqrt{3}} \cdot \tan ^{-1}\left(\frac{\tan \frac{x}{2}}{\sqrt{3}}\right)\end{aligned}\)
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