MHT CET · Maths · Differentiation
\(\frac{d}{d x}\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right)=\)
- A \(\frac{\sec ^2 x}{(1+\tan x)^{3 / 2}(1-\tan x)^{1 / 2}}\)
- B \(\frac{-\sec ^2 x}{\left(1-\tan ^2 x\right)^{1 / 2}}\)
- C \(\frac{\sec ^2 x}{\left(1-\tan ^2 x\right)^{1 / 2}}\)
- D \(\frac{-\sec ^2 x}{(1+\tan x)^{3 / 2}(1-\tan x)^{1 / 2}}\)
Answer & Solution
Correct Answer
(D) \(\frac{-\sec ^2 x}{(1+\tan x)^{3 / 2}(1-\tan x)^{1 / 2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{d x}\left(\sqrt{\frac{1-\tan x}{1+\tan x}}\right)=\frac{1}{\sqrt[2]{\frac{1-\tan x}{1+\tan x}}} \times\) \(\frac{(1+\tan x)\left(0-\sec ^2 x\right)-(1-\tan x)\left(0-\sec ^2 x\right)}{(1+\tan x)^2} \)
\( =\frac{2 \sec ^2 x}{2 \sqrt{1-\tan x}(1+\tan x)^{3 / 2}} \)
\( =\frac{\sec ^2 x}{(1-\tan x)^{1 / 2} \cdot(1+\tan x)^{3 / 2}}\)
\( =\frac{2 \sec ^2 x}{2 \sqrt{1-\tan x}(1+\tan x)^{3 / 2}} \)
\( =\frac{\sec ^2 x}{(1-\tan x)^{1 / 2} \cdot(1+\tan x)^{3 / 2}}\)
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