MHT CET · Maths · Definite Integration
\(\frac{d^{2} y}{d x^{2}}=\sin x+e^{x} ; y(0)=3\) and \(\frac{d y}{d x}\) at \(x=0\) is 4 , then the equation of the
- A \(y=4+2 x+e^{x}-\sin x\)
- B \(y=2+3 x+e^{x}-\sin x\)
- C \(y=2+4 x+e^{x}-\sin x\)
- D \(y=4+2 x+e^{x}+\sin x\)
Answer & Solution
Correct Answer
(C) \(y=2+4 x+e^{x}-\sin x\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{d x}\left(\frac{d y}{d x}\right)=\sin x+e^{x}\)
Integrating both sides.;
\(y \rightarrow \frac{d y}{d x}=e^{x}-\cos x+c\)
at \(x=0 ; \frac{d y}{d x}=4 ; \quad c=4\)
\(\frac{d y}{d x}=e^{x}-\cos x+4\)
Integrating both sides;
\(y=e^{x}-\sin x+4 x+c\)
put \(x=0 ; y(0)=3\);
\(c=2\)
Equation of curve \(y=e^{x}-\sin x+4 x+2\)
Integrating both sides.;
\(y \rightarrow \frac{d y}{d x}=e^{x}-\cos x+c\)
at \(x=0 ; \frac{d y}{d x}=4 ; \quad c=4\)
\(\frac{d y}{d x}=e^{x}-\cos x+4\)
Integrating both sides;
\(y=e^{x}-\sin x+4 x+c\)
put \(x=0 ; y(0)=3\);
\(c=2\)
Equation of curve \(y=e^{x}-\sin x+4 x+2\)
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