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MHT CET · Maths · Probability

Consider the probability distribution
\(\begin{array}{|r|c|c|c|c|c|} \hline \mathrm{X}=x & 1 & 2 & 3 & 4 & 5 \\ \hline \mathrm{P}(\mathrm{X}=x) & \mathrm{K} & 2 \mathrm{K} & \mathrm{K}^2 & 2 \mathrm{K} & 5 \mathrm{K}^2 \\ \hline \end{array}\)
Then the value of \(\mathrm{P}(\mathrm{X} > 2)\) is

  1. A \(\frac{7}{12}\)
  2. B \(\frac{1}{36}\)
  3. C \(\frac{1}{2}\)
  4. D \(\frac{23}{36}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(\sum P(X=x) = 1 \Rightarrow K + 2K + K^2 + 2K + 5K^2 = 1\) \(6K^2 + 5K - 1 = 0\)