MHT CET · Maths · Probability
Consider the probability distribution
\(\begin{array}{|r|c|c|c|c|c|} \hline \mathrm{X}=x & 1 & 2 & 3 & 4 & 5 \\ \hline \mathrm{P}(\mathrm{X}=x) & \mathrm{K} & 2 \mathrm{K} & \mathrm{K}^2 & 2 \mathrm{K} & 5 \mathrm{K}^2 \\ \hline \end{array}\)
Then the value of \(\mathrm{P}(\mathrm{X} > 2)\) is
- A \(\frac{7}{12}\)
- B \(\frac{1}{36}\)
- C \(\frac{1}{2}\)
- D \(\frac{23}{36}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\sum P(X=x) = 1 \Rightarrow K + 2K + K^2 + 2K + 5K^2 = 1\) \(6K^2 + 5K - 1 = 0\)
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