MHT CET · Maths · Complex Number
Argument of the complex number \(\mathrm{z}=\frac{13-5 \mathrm{i}}{4-9 \mathrm{i}}, i=\sqrt{-1}\) is
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{z}=\frac{13-5 \mathrm{i}}{4-9 \mathrm{i}} \times \frac{4+9 \mathrm{i}}{4+9 \mathrm{i}}\) \(\mathrm{z}=\frac{52+117 \mathrm{i}-20 \mathrm{i}-45 \mathrm{i}^{2}}{16+81}\)
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