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MHT CET · Maths · Circle

Angle between the tangents to the circle \(x^2+y^2=25 x^2\) from the point \((1,7)\) is

  1. A \(\frac{\pi}{4}\)
  2. B \(\tan ^{-1}\left(\frac{2}{5}\right)\)
  3. C \(\tan ^{-1} 2\)
  4. D \(\frac{\pi}{2}\)
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Answer & Solution

Correct Answer

(D) \(\frac{\pi}{2}\)

Step-by-step Solution

Detailed explanation


\(\begin{aligned} & \mathrm{OP}=5 \sqrt{2} \\ & \mathrm{OT}=5 \\ & \mathrm{PT}=\sqrt{\mathrm{OP}^2-\mathrm{OT}^2}=5 \\ & \Rightarrow \angle \mathrm{OPT}=45^{\circ} \\ & \Rightarrow \angle \mathrm{TPT}^{\prime}=2 \angle \mathrm{OPT}=2 \times 45^{\circ}=90^{\circ}\end{aligned}\)
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