MHT CET · Maths · Circle
Angle between the tangents to the circle \(x^2+y^2=25 x^2\) from the point \((1,7)\) is
- A \(\frac{\pi}{4}\)
- B \(\tan ^{-1}\left(\frac{2}{5}\right)\)
- C \(\tan ^{-1} 2\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & \mathrm{OP}=5 \sqrt{2} \\ & \mathrm{OT}=5 \\ & \mathrm{PT}=\sqrt{\mathrm{OP}^2-\mathrm{OT}^2}=5 \\ & \Rightarrow \angle \mathrm{OPT}=45^{\circ} \\ & \Rightarrow \angle \mathrm{TPT}^{\prime}=2 \angle \mathrm{OPT}=2 \times 45^{\circ}=90^{\circ}\end{aligned}\)
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