MHT CET · Maths · Parabola
Angle between the parabola \(y^2=4(x-1)\) and \(x^2+4(y-3)=0\) at the common end of their latus rectum is
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Parabola 1: \(y^2 = 4(x-1)\) Parabola 2: \(x^2 = -4(y-3)\)
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