MHT CET · Maths · Trigonometric Ratios & Identities
\(\begin{aligned} & \text { If } \sin (\alpha+\beta)=1, \sin (\alpha-\beta)=\frac{1}{2}, \alpha, \beta \in\left[0, \frac{\pi}{2}\right] \\ & \text { then } \tan (\alpha+2 \beta) \cdot \tan (2 \alpha+\beta)=\end{aligned}\)
- A 1
- B -1
- C 0
- D 4
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
\( \alpha+\beta = \frac{\pi}{2} \) \( \alpha-\beta = \frac{\pi}{6} \)
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