MHT CET · Maths · Differential Equations
A wet substance in the open air loses its moisture at a rate proportional to the moisture content. If a sheet, hung in the open air, loses half its moisture during the first hour, then \(90 \%\) of the moisture will be lost in ...... hours.
- A \(2 \log _2 10\)
- B \(\frac{4 \log 10}{\log 2}\)
- C \(\log _2 10\)
- D \(\frac{3 \log 10}{\log 2}\)
Answer & Solution
Correct Answer
(C) \(\log _2 10\)
Step-by-step Solution
Detailed explanation
\(M(t) = M_0 \left(\frac{1}{2}\right)^t\) \(\frac{1}{2} M_0 = M_0 \left(\frac{1}{2}\right)^1 \Rightarrow \text{This step is for confirmation of the model, not a calculation of a constant.}\)
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