MHT CET · Maths · Vector Algebra
A vector with magnitude of 3 units, which is perpendicular to each of the vectors \(\bar{a}=3 \hat{i}+\hat{j}-4 \hat{k}\) and \(\bar{b}=6 \hat{i}+5 \hat{j}-2 \hat{k}\), is given by
- A \(\pm(2 \hat{i}-2 \hat{j}+\hat{k})\)
- B \(\pm(2 \hat{i}+2 \hat{j}-\hat{k})\)
- C \(\pm(2 \hat{i}-2 \hat{j}-\widehat{k})\)
- D \(\pm(2 \hat{i}+2 \hat{j}+\hat{k})\)
Answer & Solution
Correct Answer
(A) \(\pm(2 \hat{i}-2 \hat{j}+\hat{k})\)
Step-by-step Solution
Detailed explanation
\(\text {The required vector }= \pm 3\left(\frac{\vec{a} \times \vec{b}}{|\vec{a} \times \vec{b}|}\right)= \pm\) \( \frac{3(18 \hat{i}-18 \hat{j}+9 \hat{k})}{\sqrt{18^2+18^2+9^2}}\)
\(= \pm \frac{3(18 \hat{i}-18 \hat{j}+9 \hat{k})}{27}= \pm(2 \hat{i}-2 \hat{j}+\hat{k})\)
\(= \pm \frac{3(18 \hat{i}-18 \hat{j}+9 \hat{k})}{27}= \pm(2 \hat{i}-2 \hat{j}+\hat{k})\)
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