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MHT CET · Maths · Vector Algebra

A vector \(v\) is equally inclined to the \(x\) -axis, \(y\) -axis and \(z\) -axis respectively, its direction cosines are

  1. A \(\left. < \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\right\rangle\)
  2. B \(\left. < -\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}\right\rangle\)
  3. C \( < \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}>\) or \( < -\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}>\)
  4. D None of the above
Verified Solution

Answer & Solution

Correct Answer

(C) \( < \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}>\) or \( < -\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}>\)

Step-by-step Solution

Detailed explanation

Let the vector \(\mathbf{v}\) make an angle \(\alpha\) with each of the three axes, then direction cosine of \(\mathbf{v}\) are
\(
\begin{array}{l}
< \cos \alpha, \cos \alpha, \cos \alpha> \\
\text {Also, } \cos ^{2} \alpha+\cos ^{2} \alpha+\cos ^{2} \alpha=1 \\
\Rightarrow \cos ^{2} \alpha=1 / 3 \\
\Rightarrow \cos \alpha=\pm \frac{1}{\sqrt{3}}
\end{array}
\)
Hence, direction cosine of \(\mathbf{v}\) are
\( < \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}>
\)
Or
\( < -\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}>
\)
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