MHT CET · Maths · Three Dimensional Geometry
A triangle ABC is formed by \(\mathrm{A}(1,-1,0), \mathrm{B}(3,5,3), \mathrm{C}(-11,-5,6)\). The equation of internal angle bisector of angle \(A\) is
- A \(\frac{(1-x)}{2}=\frac{y-(-1)}{2}=\frac{z}{3}\)
- B \(\frac{x+1}{2}=\frac{y-1}{2}=\frac{z}{3}\)
- C \(\frac{x+2}{1}=\frac{y-2}{1}=\frac{z}{3}\)
- D \(\frac{x-2}{1}=\frac{y+3}{2}=\frac{z}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{(1-x)}{2}=\frac{y-(-1)}{2}=\frac{z}{3}\)
Step-by-step Solution
Detailed explanation
\( \vec{AB} = (3-1, 5-(-1), 3-0) = (2, 6, 3) \) \( \vec{AC} = (-11-1, -5-(-1), 6-0) = (-12, -4, 6) \)
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