MHT CET · Maths · Probability
A random variable \(\mathrm{X}\) has the following probability distribution

Then \(F(4)=\)
- A \(\frac{3}{10}\)
- B \(\frac{1}{10}\)
- C \(\frac{7}{10}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{4}{5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Here } \mathrm{k}+2 \mathrm{k}+2 \mathrm{k}+3 \mathrm{k}+\mathrm{k}^2+2 \mathrm{k}^2+7 \mathrm{k}^2+\mathrm{k}=1 \\ & \therefore 10 \mathrm{k}^2+9 \mathrm{k}-1=0 \Rightarrow(10 \mathrm{k}-1)(\mathrm{k}+1)=0 \\ & \therefore \mathrm{k}=\frac{1}{10} \quad \ldots(\mathrm{k} \geq 0) \\ & \therefore \mathrm{F}(4)=\mathrm{k}+2 \mathrm{k}+2 \mathrm{k}+3 \mathrm{k}=8 \mathrm{k}=\frac{8}{10}=\frac{4}{5}\end{aligned}\)
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