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MHT CET · Maths · Probability

A random variable \(\mathrm{X}\) has the following probability distribution

Then \(F(4)=\)

  1. A \(\frac{3}{10}\)
  2. B \(\frac{1}{10}\)
  3. C \(\frac{7}{10}\)
  4. D \(\frac{4}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{4}{5}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { Here } \mathrm{k}+2 \mathrm{k}+2 \mathrm{k}+3 \mathrm{k}+\mathrm{k}^2+2 \mathrm{k}^2+7 \mathrm{k}^2+\mathrm{k}=1 \\ & \therefore 10 \mathrm{k}^2+9 \mathrm{k}-1=0 \Rightarrow(10 \mathrm{k}-1)(\mathrm{k}+1)=0 \\ & \therefore \mathrm{k}=\frac{1}{10} \quad \ldots(\mathrm{k} \geq 0) \\ & \therefore \mathrm{F}(4)=\mathrm{k}+2 \mathrm{k}+2 \mathrm{k}+3 \mathrm{k}=8 \mathrm{k}=\frac{8}{10}=\frac{4}{5}\end{aligned}\)