MHT CET · Maths · Application of Derivatives
A population \(\mathrm{p}(\mathrm{t})\) of 1000 bacteria introduced into a nutrient medium grows according to the relation \(\mathrm{p}(\mathrm{t})=1000+\frac{1000 \mathrm{t}}{100+\mathrm{t}^2}\). The maximum size of this bacterial population is
- A \(1100\)
- B \(1250\)
- C \(1050\)
- D \(950\)
Answer & Solution
Correct Answer
(C) \(1050\)
Step-by-step Solution
Detailed explanation
\(\mathrm{p}'(\mathrm{t})=\frac{d}{dt}\left(1000+\frac{1000 \mathrm{t}}{100+\mathrm{t}^2}\right)\) \(\mathrm{p}'(\mathrm{t})=0+1000 \frac{1 \cdot (100+\mathrm{t}^2) - \mathrm{t} \cdot (2\mathrm{t})}{(100+\mathrm{t}^2)^2}\)
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