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MHT CET · Maths · Application of Derivatives

A population \(\mathrm{p}(\mathrm{t})\) of 1000 bacteria introduced into a nutrient medium grows according to the relation \(\mathrm{p}(\mathrm{t})=1000+\frac{1000 \mathrm{t}}{100+\mathrm{t}^2}\). The maximum size of this bacterial population is

  1. A \(1100\)
  2. B \(1250\)
  3. C \(1050\)
  4. D \(950\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1050\)

Step-by-step Solution

Detailed explanation

\(\mathrm{p}'(\mathrm{t})=\frac{d}{dt}\left(1000+\frac{1000 \mathrm{t}}{100+\mathrm{t}^2}\right)\) \(\mathrm{p}'(\mathrm{t})=0+1000 \frac{1 \cdot (100+\mathrm{t}^2) - \mathrm{t} \cdot (2\mathrm{t})}{(100+\mathrm{t}^2)^2}\)