MHT CET · Maths · Probability
A player tosses 2 fair coins. He with Rs. 5 if 2 heads appear, Rs. 2 if 1 head appears and Rs. 1 if no head appear, then the variance of his winning amount is
- A \(\frac{9}{4}\)
- B 6
- C \(\frac{5}{2}\)
- D \(\frac{17}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{9}{4}\)
Step-by-step Solution
Detailed explanation
Variance \(=\sum p_i x_i{ }^2-\left(\sum p_i x_i\right)^2\)
\(=\frac{17}{2}-\frac{25}{4}=\frac{9}{4}\)
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