MHT CET · Maths · Application of Derivatives
A particle moves according to the law \(s=t^{3}-6 t^{2}+9 t+25 .\) The displacement of
- A 0 units
- B -27 units
- C 27 units
- D 9 units
Answer & Solution
Correct Answer
(C) 27 units
Step-by-step Solution
Detailed explanation
Given \(s=t^{3}-6 t^{2}+9 t+25\) ....(1)
\(
\begin{array}{l}v=\frac{d s}{d t}=3 t^{2}-12 t+9 \\ \frac{d v}{d t}=6 t-12\end{array}
\)
Given \(6 t-12=0 \Rightarrow t=2\)
\(\therefore\) from \((1), s=(2)^{3}-6 \times 4+18+25=27\)
\(
\begin{array}{l}v=\frac{d s}{d t}=3 t^{2}-12 t+9 \\ \frac{d v}{d t}=6 t-12\end{array}
\)
Given \(6 t-12=0 \Rightarrow t=2\)
\(\therefore\) from \((1), s=(2)^{3}-6 \times 4+18+25=27\)
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