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MHT CET · Maths · Application of Derivatives

A particle moves according to the law \(s=t^{3}-6 t^{2}+9 t+25 .\) The displacement of

  1. A 0 units
  2. B -27 units
  3. C 27 units
  4. D 9 units
Verified Solution

Answer & Solution

Correct Answer

(C) 27 units

Step-by-step Solution

Detailed explanation

Given \(s=t^{3}-6 t^{2}+9 t+25\) ....(1)
\(
\begin{array}{l}v=\frac{d s}{d t}=3 t^{2}-12 t+9 \\ \frac{d v}{d t}=6 t-12\end{array}
\)
Given \(6 t-12=0 \Rightarrow t=2\)
\(\therefore\) from \((1), s=(2)^{3}-6 \times 4+18+25=27\)