MHT CET · Maths · Probability
A pair of fair dice is thrown 4 times. If getting the same number on both dice is considered as a success, then the probability of two successes are
- A \(\frac{25}{216}\)
- B \(\frac{25}{36}\)
- C \(\frac{25}{108}\)
- D \(\frac{25}{104}\)
Answer & Solution
Correct Answer
(A) \(\frac{25}{216}\)
Step-by-step Solution
Detailed explanation
\(p = \frac{6}{36} = \frac{1}{6}\) \(P(\text{2 successes}) = C(4, 2) \left(\frac{1}{6}\right)^2 \left(1-\frac{1}{6}\right)^{4-2}\)
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