MHT CET · Maths · Vector Algebra
\(\bar{a}=\hat{i}-\hat{\mathrm{j}}, \overline{\mathrm{b}}=\hat{\mathrm{j}}-\hat{\mathrm{k}}, \overline{\mathrm{c}}=\hat{\mathrm{k}}-\hat{i}\) then a unit vector \(\overline{\mathrm{d}}\) such that \(\bar{a} \cdot \bar{d}=0=[\bar{b} \bar{c} \bar{d}]\) is
- A \(\pm\left(\frac{\hat{i}+\hat{j}+3 \hat{k}}{\sqrt{11}}\right)\)
- B \(\pm\left(\frac{-\hat{\mathrm{j}}+\hat{\mathrm{k}}}{\sqrt{2}}\right)\)
- C \(\pm\left(\frac{\hat{i}+\hat{j}+\hat{k}}{\sqrt{3}}\right)\)
- D \(\pm\left(\frac{\hat{i}+\hat{j}-2 \hat{k}}{\sqrt{6}}\right)\)
Answer & Solution
Correct Answer
(D) \(\pm\left(\frac{\hat{i}+\hat{j}-2 \hat{k}}{\sqrt{6}}\right)\)
Step-by-step Solution
Detailed explanation
\(\text{Let } \bar{d} = x\hat{i} + y\hat{j} + z\hat{k}\). \(\bar{a} \cdot \bar{d}=0 \Rightarrow (\hat{i}-\hat{j}) \cdot (x\hat{i} + y\hat{j} + z\hat{k})=0 \Rightarrow x-y=0 \Rightarrow x=y\).
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