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MHT CET · Maths · Linear Programming

A diet of a sick person must contain atleast 4000 unit of vitamins, 50 unit of proteins and 1400 calories. Two foods \(\mathrm{A}\) and \(\mathrm{B}\) are available at cost of ₹ \(4\) and ₹ \(3\) per unit respectively. If one unit of A contains 200 unit of vitamins, 1 unit of protein and 40 calories, while one unit of food B contains 100 unit of vitamins, 2 unit of protein and 40 calories. Formulate the problem, so that the diet be cheapest.

  1. A \(200 x+100 y \geq 4000, x+2 y \geq 50\)
    \(40 x+40 y \geq 1400, x \geq 0\) and \(y \geq 0\)
    \(O . F z=4 x+3 y\)
  2. B \(400 x+200 y \geq 100, x+2 y \geq 50\)
    \(40 x+40 y \geq 1400, x \geq 0\) and \(y \geq 0\)
    O. \(F z=4 x+3 y\)
  3. C \(100 x+200 y \geq 4000, x+2 y \geq 50\),
    \(40 x+40 y \geq 1400, x \geq 0\) and \(y \geq 0\)
    O. \(F z=4 x+3 y\)
  4. D None of the above
Verified Solution

Answer & Solution

Correct Answer

(A) \(200 x+100 y \geq 4000, x+2 y \geq 50\)
\(40 x+40 y \geq 1400, x \geq 0\) and \(y \geq 0\)
\(O . F z=4 x+3 y\)

Step-by-step Solution

Detailed explanation

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Let \(z\) be the profit function and \(x\) and \(y\) denote the productivity of food \(A\) and \(B\) respectively. Then
\(200 x+100 y \geq 4000 \)
\( x+2 y \geq 50 \)
\( 40 x+40 \geq 1400 \)
\( \text {O.F } z=4 x+3 y, \quad x \geq 0 \text { and } y \geq 0\)