MHT CET · Maths · Probability
A coin is tossed and a die is thrown. The probability that the outcome will be head or a number greater than 4 or both, is
- A \(\frac{2}{3}\)
- B \(\frac{1}{6}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
The probability of getting head when a coin is thrown \(=\frac{1}{2}\) The probability of getting a number greater than 4 when a die is thrown
\(=\frac{2}{6}=\frac{1}{3}\)
Hence required probability \(=\left(\frac{1}{2}\right)\left(\frac{2}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)=\frac{4}{6}=\frac{2}{3}\)
\(=\frac{2}{6}=\frac{1}{3}\)
Hence required probability \(=\left(\frac{1}{2}\right)\left(\frac{2}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)=\frac{4}{6}=\frac{2}{3}\)
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