MHT CET · Maths · Probability
A box contains 8 red and \(x\) number of green balls. 3 balls are drawn at random, if the probability that 3 balls being red is \(\frac{7}{15}\) then number of green balls is _______
- A 2
- B 4
- C 3
- D 5
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
\(\frac{\binom{8}{3}}{\binom{8+x}{3}} = \frac{7}{15}\) \(\frac{56}{\frac{(8+x)(7+x)(6+x)}{6}} = \frac{7}{15}\)
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