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MHT CET · Maths · Vector Algebra

\(\overrightarrow{\mathbf{a}} \times[\overrightarrow{\mathbf{a}} \times(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}})]\) is equal to

  1. A \((\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{a}}) \cdot(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}})\)
  2. B \(\overrightarrow{\mathbf{a}} \cdot(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}})-\overrightarrow{\mathbf{b}}(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}})\)
  3. C \([\overrightarrow{\mathbf{a}} \cdot(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}})] \overrightarrow{\mathbf{a}}\)
  4. D \((\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}})(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}})\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}})(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}})\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{\mathbf{a}} \times[\overrightarrow{\mathbf{a}}\times(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}})] \)
\( =\overrightarrow{\mathbf{a}} \times\{(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}) \overrightarrow{\mathbf{a}}-(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}}) \overrightarrow{\mathbf{b}}\} \)
\( =(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}})(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{a}})-(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}})(\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}) \)
\( =(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}) 0+(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}})(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}}) \)
\( =(\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{a}})(\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{a}})\)