MHT CET · Maths · Indefinite Integration
\(\int \sin ^5 x \mathrm{~d} x=\)
- A \(\cos x+\frac{2}{3} \cos ^2 x-\frac{\cos ^5 x}{5}+c \quad\), where \(c\) is the constant of integration
- B \(\cos x+\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+c \quad, \quad\) where \(c\) is the constant of integration
- C \(-\left(\cos x-\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+c\right)\), where \(c\) is the constant of integration
- D \(\cos x-\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+c, \quad\) where \(c\) is the constant of integration
Answer & Solution
Correct Answer
(C) \(-\left(\cos x-\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+c\right)\), where \(c\) is the constant of integration
Step-by-step Solution
Detailed explanation
\(\int \sin^5 x \, \mathrm{d}x = \int (\sin^2 x)^2 \sin x \, \mathrm{d}x = \int (1-\cos^2 x)^2 \sin x \, \mathrm{d}x\) Let \(u = \cos x\), then \( \mathrm{d}u = -\sin x \, \mathrm{d}x \).
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