MHT CET · Maths · Indefinite Integration
\(\int \frac{\sin \frac{5 x}{2}}{\sin \frac{x}{2}} d x=\)
(where \(C\) is a constant of integration.)
- A \(x+\sin x+2 \sin 2 x+C\)
- B \(x+2 \sin x+2 \sin 2 x+C\)
- C \(x+2 \sin x+\sin 2 x+C\)
- D \(x+\sin x+\sin 2 x+C\)
Answer & Solution
Correct Answer
(C) \(x+2 \sin x+\sin 2 x+C\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \int \frac{\sin \frac{5 x}{2}}{\sin \frac{x}{2}} d x=\int \frac{\sin \left(\frac{x}{2}+2 x\right)}{\sin \frac{x}{2}} d x \\ & =\int \frac{\sin \frac{x}{2} \cos 2 x+\cos \frac{x}{2} \sin 2 x}{\sin \frac{x}{2}} d x \\ & \int\left(\cos 2 x+\cos \frac{x}{2} \cdot 4 \cos \frac{x}{2} \cdot \cos x\right) d x \\ & =\int(\cos 2 x+2(1+\cos x) \cos x) d x \\ & =\int\left(\cos 2 x+2 \cos x+2 \cos ^2 x\right) d x \\ & =\int(\cos 2 x+2 \cos x+1+\cos 2 x) d x\end{aligned}\)
\(\begin{aligned} & =\int(1+2 \cos x+2 \cos x) d x \\ & =x+2 \sin x+\sin 2 x+C\end{aligned}\)
\(\begin{aligned} & =\int(1+2 \cos x+2 \cos x) d x \\ & =x+2 \sin x+\sin 2 x+C\end{aligned}\)
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