MHT CET · Maths · Definite Integration
\(\int_3^5 \frac{\sqrt{x} d x}{\sqrt{8-x}+\sqrt{x}}=\)
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
Let \(I = \int_3^5 \frac{\sqrt{x} d x}{\sqrt{8-x}+\sqrt{x}}\). Using \(\int_a^b f(x) dx = \int_a^b f(a+b-x) dx\): \(I = \int_3^5 \frac{\sqrt{8-x} d x}{\sqrt{x}+\sqrt{8-x}}\).
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