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MHT CET · Maths · Definite Integration

\(\int_3^5 \frac{\sqrt{x} d x}{\sqrt{8-x}+\sqrt{x}}=\)

  1. A 0
  2. B 1
  3. C 2
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(B) 1

Step-by-step Solution

Detailed explanation

Let \(I = \int_3^5 \frac{\sqrt{x} d x}{\sqrt{8-x}+\sqrt{x}}\). Using \(\int_a^b f(x) dx = \int_a^b f(a+b-x) dx\): \(I = \int_3^5 \frac{\sqrt{8-x} d x}{\sqrt{x}+\sqrt{8-x}}\).