MHT CET · Maths · Trigonometric Ratios & Identities
\(\cos \left(\frac{3 \pi}{4}+x\right)-\sin \left(\frac{\pi}{4}-x\right)=\)
- A \(-\sqrt{2} \cos x\)
- B \(-\sqrt{2} \sin x\)
- C \(\sqrt{2} \cos x\)
- D \(\sqrt{2} \sin x\)
Answer & Solution
Correct Answer
(A) \(-\sqrt{2} \cos x\)
Step-by-step Solution
Detailed explanation
\(\cos \left(\frac{3 \pi}{4}+x\right)-\sin \left(\frac{\pi}{4}-x\right)\)
\(=\left(\cos \frac{3 \pi}{4} \cos x-\sin \frac{3 \pi}{4} \sin x\right)-\left(\sin \frac{\pi}{4} \cos x-\cos \frac{\pi}{4} \sin x\right)\)
\(=\frac{-1}{\sqrt{2}} \cos x-\frac{1}{\sqrt{2}} \sin x-\frac{1}{\sqrt{2}} \cos x+\frac{1}{\sqrt{2}} \sin x\)
\(=-\sqrt{2} \cos x\)
\(=\left(\cos \frac{3 \pi}{4} \cos x-\sin \frac{3 \pi}{4} \sin x\right)-\left(\sin \frac{\pi}{4} \cos x-\cos \frac{\pi}{4} \sin x\right)\)
\(=\frac{-1}{\sqrt{2}} \cos x-\frac{1}{\sqrt{2}} \sin x-\frac{1}{\sqrt{2}} \cos x+\frac{1}{\sqrt{2}} \sin x\)
\(=-\sqrt{2} \cos x\)
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