MHT CET · Maths · Permutation Combination
21 friends were invited for a party. Two round tables can accommodate 12 and 9 friends each. The number of ways of the seating arrangements of friends is .....
- A \(11!\times 8!\)
- B \(12!\times 9!\)
- C \(\frac{35}{9} \times 19!\)
- D \(\frac{20!}{12!8!} \times 11!\times 9!\)
Answer & Solution
Correct Answer
(C) \(\frac{35}{9} \times 19!\)
Step-by-step Solution
Detailed explanation
Number of ways = \(\binom{21}{12} \times (12-1)! \times (9-1)!\) = \(\frac{21!}{12!9!} \times 11! \times 8!\)
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