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MHT CET · Maths · Application of Derivatives

20 is divided into two parts so that the product of the cube of one part and the square of the other part is maximum, then these two parts are

  1. A 15,5
  2. B 16,4
  3. C 12,8
  4. D 14,6
Verified Solution

Answer & Solution

Correct Answer

(C) 12,8

Step-by-step Solution

Detailed explanation

Let the parts be \(x\) and \(y\). \(x + y = 20 \Rightarrow y = 20 - x\). Function to maximize: \(P = x^3 y^2 = x^3 (20 - x)^2\).
From MHT CET
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