MHT CET · Maths · Indefinite Integration
\(\int \frac{\sin 2 x \cos 2 x}{\sqrt{4-\cos ^4 2 x}} \mathrm{~d} x=\)
- A \(\frac{1}{4} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+c \quad\), where \(c\) is the constant of integration.
- B \(\frac{-1}{4} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+c\), where \(c\) is the constant of integration.
- C \(\frac{1}{2} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+c \quad\), where \(c\) is the constant of integration.
- D \(\frac{-1}{2} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+c \quad\), where \(c\) is the constant of integration.
Answer & Solution
Correct Answer
(B) \(\frac{-1}{4} \sin ^{-1}\left(\frac{\cos ^2 2 x}{2}\right)+c\), where \(c\) is the constant of integration.
Step-by-step Solution
Detailed explanation
Let \(u = \cos^2 2x\). \(du = -4 \sin 2x \cos 2x \mathrm{~d}x\)
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