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MHT CET · Maths · Indefinite Integration

\( \int \frac{2 x^2-1}{x^4-x^2-20} d x= \)

  1. A \(\frac{1}{\sqrt{5}} \log \left|\frac{\mathrm{x}+\sqrt{5}}{\mathrm{x}-\sqrt{5}}\right|+\tan ^{-1}\left(\frac{\mathrm{x}}{2}\right)+\mathrm{c}\)
  2. B \(\frac{1}{2 \sqrt{5}} \log \left|\frac{\mathrm{x}+\sqrt{5}}{\mathrm{x}-\sqrt{5}}\right|+\tan ^{-1}\left(\frac{\mathrm{x}}{2}\right)+\mathrm{c}\)
  3. C \(\frac{1}{2 \sqrt{5}} \log \left|\frac{\mathrm{x}-\sqrt{5}}{\mathrm{x}+\sqrt{5}}\right|+\frac{1}{2} \tan ^{-1}\left(\frac{\mathrm{x}}{2}\right)+\mathrm{c}\)
  4. D \(\frac{1}{2} \log \left|\frac{\mathrm{x}-\sqrt{5}}{\mathrm{x}+\sqrt{5}}\right|+\frac{1}{2} \tan ^{-1}\left(\frac{\mathrm{x}}{2}\right)+\mathrm{c}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2 \sqrt{5}} \log \left|\frac{\mathrm{x}-\sqrt{5}}{\mathrm{x}+\sqrt{5}}\right|+\frac{1}{2} \tan ^{-1}\left(\frac{\mathrm{x}}{2}\right)+\mathrm{c}\)

Step-by-step Solution

Detailed explanation

Let \(I=\int \frac{2 x^2-1}{x^4-x^2-20} d x\)
If \(x^2=t\), then \(\frac{2 x^2-1}{x^4-x^2-20}=\frac{2 t-1}{t^2-t-20}\)
Let \(\frac{2 t-1}{(t-5)(t+4)}=\frac{A}{(t-5)}+\frac{B}{(t+4)}\)
\(
\begin{aligned}
& \therefore 2 \mathrm{t}-1=(\mathrm{t}+4) \mathrm{a}+(\mathrm{t}-5) \mathrm{B} \\
& \therefore 2=\mathrm{A}+\mathrm{B} \text { and }-1=4 \mathrm{~A}-5 \mathrm{~B}
\end{aligned}
\)
Solving, we get \(\mathrm{B}=1, \mathrm{~A}=1\)
\(
\therefore I=\int\left[\frac{1}{x^2-5}+\frac{1}{x^2+4}\right] d x=\frac{1}{2 \sqrt{5}} \log\) \(\left|\frac{x-\sqrt{5}}{x+\sqrt{5}}\right|+\frac{1}{2} \tan ^{-1}\left(\frac{x}{2}\right)+c
\)