MHT CET · Maths · Vector Algebra
\((2 \hat{i}+6 \hat{i}+27 \hat{k}) \times(\hat{i}+\lambda \hat{j}+\mu \hat{k})=\overline{0}\), then \(\lambda\) and \(\mu\) are respectively
- A \(\frac{17}{2}, 3\)
- B \(3, \frac{17}{2}\)
- C \(3, \frac{27}{2}\)
- D \(\frac{27}{2}, 3\)
Answer & Solution
Correct Answer
(C) \(3, \frac{27}{2}\)
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