MHT CET · Maths · Definite Integration
\(\int_2^4 \frac{\log x^2}{\log x^2+\log \left(36-12 x+x^2\right)} \mathrm{d} x\) is equal to
- A \(1\)
- B \(2\)
- C \(4\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
Let \(I = \int_2^4 \frac{\log x^2}{\log x^2+\log \left(36-12 x+x^2\right)} \mathrm{d} x\) \(I = \int_2^4 \frac{\log x^2}{\log x^2+\log (6-x)^2} \mathrm{d} x\)
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