MHT CET · Maths · Indefinite Integration
\(\int \sec ^{\frac{2}{3}} x \cdot \operatorname{cosec}^{\frac{4}{3}} x \mathrm{~d} x=\)
- A \(3 \tan ^{\frac{-1}{3}} x+c\), where \(c\) is the constant of integration
- B \(-3 \tan ^{\frac{-1}{3}} x+c\), where \(c\) is the constant of integration
- C \(-3 \cot ^{\frac{-1}{3}} x+c\), where \(c\) is the constant of integration
- D \(-\frac{3}{4} \tan ^{\frac{-4}{3}} x+c\), where \(c\) is the constant of integration
Answer & Solution
Correct Answer
(B) \(-3 \tan ^{\frac{-1}{3}} x+c\), where \(c\) is the constant of integration
Step-by-step Solution
Detailed explanation
\( \int \sec ^{\frac{2}{3}} x \cdot \operatorname{cosec}^{\frac{4}{3}} x \mathrm{~d} x = \int \frac{\sec^2 x}{\tan^{\frac{4}{3}} x} \mathrm{~d} x \) Let \( u = \tan x \Rightarrow \mathrm{d} u = \sec^2 x \mathrm{~d} x \)
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