MHT CET · Maths · Definite Integration
\(\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\left(x^2+\log \left(\frac{\pi-x}{\pi+x}\right) \cdot \cos x\right) \mathrm{d} x=\)
- A \(0\)
- B \(\frac{\pi^3}{48}\)
- C \(\frac{\pi^3}{12}\)
- D \(\frac{\pi^3}{24}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi^3}{12}\)
Step-by-step Solution
Detailed explanation
\(\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\left(x^2+\log \left(\frac{\pi-x}{\pi+x}\right) \cdot \cos x\right) \mathrm{d} x = \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} x^2 \mathrm{d} x + \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \log \left(\frac{\pi-x}{\pi+x}\right) \cdot \cos x \mathrm{d} x\) As \(x^2\) is an even function and \(\log \left(\frac{\pi-x}{\pi+x}\right) \cdot \cos x\) is an odd function \((f(-x) = -\log \left(\frac{\pi-x}{\pi+x}\right) \cdot \cos x = -f(x))\), the integral becomes:
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