ExamBro
ExamBro
MHT CET · Maths · Definite Integration

\(\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \sin ^{2} x d x=\)

  1. A \(\frac{\pi}{4}\)
  2. B \(\frac{\pi}{3}\)
  3. C \(\frac{\pi}{2}\)
  4. D \(\frac{3 \pi}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\pi}{2}\)

Step-by-step Solution

Detailed explanation

Let \(f(x)=\sin ^{2} x\)
\(\therefore \mathrm{f}(-\mathrm{x})=[\sin (-\mathrm{x})]^{2}=\sin ^{2} \mathrm{x}\)
Thus \(\sin ^{2} x\) is an even function.
\(\therefore \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \sin ^{2} x d x=2 \int_{0}^{\frac{\pi}{2}} \sin ^{2} x d x\)
\(=2 \int_{0}^{\frac{\pi}{2}} \frac{1}{2}(1-\cos 2 x) d x=\left[x-\frac{\sin 2 x}{2}\right]_{0}^{\frac{\pi}{2}}\)
\(=\left(\frac{\pi}{2}-0\right)-\left(\frac{\sin \pi}{2}-\frac{\sin 0}{2}\right)=\frac{\pi}{2}\)