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MHT CET · Maths · Definite Integration

\(\int_1^{\mathrm{e}} \frac{\mathrm{e}^x}{x}(1+x \log x) \mathrm{d} x=\)

  1. A \(e^e\)
  2. B \(\mathrm{e}^{\mathrm{e}}-\mathrm{e}\)
  3. C \(e^e+e\)
  4. D e
Verified Solution

Answer & Solution

Correct Answer

(A) \(e^e\)

Step-by-step Solution

Detailed explanation

\(\int \mathrm{e}^x (\log x + \frac{1}{x}) \mathrm{d}x = \mathrm{e}^x \log x\) \([\mathrm{e}^x \log x]_1^{\mathrm{e}} = \mathrm{e}^{\mathrm{e}} \log \mathrm{e} - \mathrm{e}^1 \log 1\)