MHT CET · Maths · Definite Integration
\(\int_{-1}^3\left(\tan ^{-1}\left(\frac{x}{x^2+1}\right)+\tan ^{-1}\left(\frac{x^2+1}{x}\right)\right) \mathrm{d} x=\)
- A \(\frac{\pi}{2}\)
- B \(\pi\)
- C \(\frac{2 \pi}{3}\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(B) \(\pi\)
Step-by-step Solution
Detailed explanation
For \(y = \frac{x}{x^2+1}\), the integrand is \(\tan^{-1}(y) + \tan^{-1}\left(\frac{1}{y}\right)\). \(\tan^{-1}(y) + \tan^{-1}\left(\frac{1}{y}\right) = \frac{\pi}{2}\) for \(y>0\) and \(-\frac{\pi}{2}\) for \(y<0\).
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