MHT CET · Maths · Definite Integration
\(\int_{-1 / 2}^{1 / 2} \log \left(\frac{1+x}{1-x}\right) \mathrm{d} x=\)
- A \(0\)
- B \(\frac{1}{2}\)
- C \(-1\)
- D \(-\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\int_{\frac{-1}{2}}^{1 / 2} \log \left(\frac{1+x}{1-x}\right) \mathrm{d} x=0\left[\because \int_{-a}^a f(x) \mathrm{d} x=0\right.\) if \(f(x)\) is odd \(]\)
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