MHT CET · Maths · Definite Integration
\(\int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) d x=\)
- A 1
- B -1
- C 0
- D 2
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) \mathrm{d} x=0 \\ & \because \log \left(\frac{2-x}{2+x}\right) \text { is an odd function. }\end{aligned}\)
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