MHT CET · Maths · Definite Integration
\(\int_0^2|2 x-3| d x=\)
- A \(\frac{3}{10}\)
- B \(\frac{5}{2}\)
- C \(\frac{10}{3}\)
- D \(\frac{2}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{2}\)
Step-by-step Solution
Detailed explanation
Let
When \(x=\frac{3}{2}, 2 x-3=0\)
\( \therefore \mathrm{I}=\int_0^{3 / 2}(3-2 \mathrm{x}) \mathrm{dx}+\int_{\frac{3}{2}}^2(2 \mathrm{x}-3) \mathrm{dx}=\) \([3 \mathrm{x}]_0^{3 / 2}-\frac{2}{2}\left[\mathrm{x}^2\right]_{3 / 2}^2-[3 \mathrm{x}]_{3 / 2}^2 \)
\( =\left(\frac{9}{2}\right)-\left(\frac{9}{4}\right)+\left(4-\frac{9}{4}\right)-3\left(2-\frac{3}{2}\right)=\frac{5}{2}\)
When \(x=\frac{3}{2}, 2 x-3=0\)
\( \therefore \mathrm{I}=\int_0^{3 / 2}(3-2 \mathrm{x}) \mathrm{dx}+\int_{\frac{3}{2}}^2(2 \mathrm{x}-3) \mathrm{dx}=\) \([3 \mathrm{x}]_0^{3 / 2}-\frac{2}{2}\left[\mathrm{x}^2\right]_{3 / 2}^2-[3 \mathrm{x}]_{3 / 2}^2 \)
\( =\left(\frac{9}{2}\right)-\left(\frac{9}{4}\right)+\left(4-\frac{9}{4}\right)-3\left(2-\frac{3}{2}\right)=\frac{5}{2}\)
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