MHT CET · Maths · Definite Integration
\(\int_0^1 \log (x+1) \mathrm{d} x=\)
- A \(\log 2-1\)
- B \(\log 2+1\)
- C \(2 \log 2+1\)
- D \(2 \log 2-1\)
Answer & Solution
Correct Answer
(D) \(2 \log 2-1\)
Step-by-step Solution
Detailed explanation
\(\int_0^1 \log (x+1) \mathrm{d} x = [(x+1)\log(x+1) - x]_0^1\) \(= ( (1+1)\log(1+1) - 1 ) - ( (0+1)\log(0+1) - 0 )\)
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