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MHT CET · Maths · Definite Integration

\(\int_0^1 \tan ^{-1} x d x=\)

  1. A \(\frac{\pi}{4}-\log 2\)
  2. B \(\frac{\pi}{4}-\log \sqrt{2}\)
  3. C \(\frac{\pi}{4}+\log 2\)
  4. D \(\frac{\pi}{4}+\log \sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\pi}{4}-\log \sqrt{2}\)

Step-by-step Solution

Detailed explanation

\(\int_0^1 \tan^{-1}x dx = [x\tan^{-1}x]_0^1 - \int_0^1 \frac{x}{1+x^2}dx\) \(= [x\tan^{-1}x - \frac{1}{2}\log(1+x^2)]_0^1\)