MHT CET · Chemistry · Solid State
Xenon crystallizes in fcc lattice and the edge length of unit cell is \(620 \mathrm{pm}\). What is the radius of Xe atom?
- A 219.2pm
- B 438.5pm
- C 265.5pm
- D 536.9pm
Answer & Solution
Correct Answer
(A) 219.2pm
Step-by-step Solution
Detailed explanation
(D)
\(a=620 \mathrm{pm}\)
For fcc unit cell, \(r=\frac{a}{2 \sqrt{2}}\)
\(\therefore r=\frac{620}{2 \times 1.414}=219.2 \mathrm{pm}\)
\(a=620 \mathrm{pm}\)
For fcc unit cell, \(r=\frac{a}{2 \sqrt{2}}\)
\(\therefore r=\frac{620}{2 \times 1.414}=219.2 \mathrm{pm}\)
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