MHT CET · Chemistry · Solutions
Which of the following solutions exhibits lowest value of boiling point elevation assuming complete dissociation?
- A \(0.1 \mathrm{~m} \mathrm{AlCl}_3\)
- B \(0.01 \mathrm{~m} \mathrm{MgCl}_2\)
- C \(1 \mathrm{~m} \mathrm{KCl}\)
- D \(0.5 \mathrm{~m} \mathrm{NaCl}\)
Answer & Solution
Correct Answer
(B) \(0.01 \mathrm{~m} \mathrm{MgCl}_2\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{|l|l|c|}
\hline & {1}{|c|}{ Solution } & \begin{array}{c}
Moles of particles in \\
\mathbf{1} \mathbf{~ k g ~ s o l u t i o n ~}
\end{array} \\
\hline (A) & 0.1 \mathrm{~m} \mathrm{AlCl}_3 & 0.4 \\
\hline (B) & 0.01 \mathrm{~m} \mathrm{AlCl}_2 & 0.03 \\
\hline (C) & 1 \mathrm{~m} \mathrm{KCl} & 2 \\
\hline (D) & 0.5 \mathrm{~m} \mathrm{NaCl} & 1 \\
\hline
\end{array}\)
\(0.01 \mathrm{~m} \mathrm{MgCl}_2\) solution has minimum number of particles in solution, so it shows the lowest value of boiling point elevation.
\hline & {1}{|c|}{ Solution } & \begin{array}{c}
Moles of particles in \\
\mathbf{1} \mathbf{~ k g ~ s o l u t i o n ~}
\end{array} \\
\hline (A) & 0.1 \mathrm{~m} \mathrm{AlCl}_3 & 0.4 \\
\hline (B) & 0.01 \mathrm{~m} \mathrm{AlCl}_2 & 0.03 \\
\hline (C) & 1 \mathrm{~m} \mathrm{KCl} & 2 \\
\hline (D) & 0.5 \mathrm{~m} \mathrm{NaCl} & 1 \\
\hline
\end{array}\)
\(0.01 \mathrm{~m} \mathrm{MgCl}_2\) solution has minimum number of particles in solution, so it shows the lowest value of boiling point elevation.
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