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MHT CET · Chemistry · Chemical Bonding and Molecular Structure

Which of the following molecule has bond order 2?

  1. A \(\mathrm{N}_2\)
  2. B \(\mathrm{H}_2\)
  3. C \(\mathrm{O}_2\)
  4. D \(\mathrm{F}_2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{O}_2\)

Step-by-step Solution

Detailed explanation

The electronic configuration of \(\mathrm{O}_2\) molecule is
\(\begin{aligned}
& (\sigma 1 \mathrm{~s})^2\left(\sigma^* 1 \mathrm{~s}\right)^2(\sigma 2 \mathrm{~s})^2\left(\sigma^* 2 \mathrm{~s}\right)^2\left(\sigma 2 \mathrm{p}_{\mathrm{z}}\right)^2\left(\pi 2 \mathrm{p}_{\mathrm{x}}\right)^2 \\
& \left(\pi 2 \mathrm{p}_{\mathrm{y}}\right)^2\left(\pi^* 2 \mathrm{p}_{\mathrm{x}}\right)^1\left(\pi^* 2 \mathrm{p}_{\mathrm{y}}\right)^1
\end{aligned}\)
Bond order of \(\mathrm{O}_2\) molecule
\(=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{10-6}{2}=2\)