MHT CET · Chemistry · p Block Elements (Group 13 & 14)

Which of the following metal halide is more covalent?

A $S n C l_{2}$
B $P b C l_{2}$
C $S b C l_{3}$
D $S b C l_{5}$

Verified Solution

Answer & Solution

Correct Answer

(D) $S b C l_{5}$

Step-by-step Solution

Detailed explanation

Key Idea Fajan’s rules help in predicting the covalent character in bond.

S b C l_{5}

metal halide is more covalent than other given options. It can be explained on the basis of Fajan’s rule. Higher the charge on the cation, greater is its polarising power. In

S b C l_{5},

Antimony (Sb) is in + 5 oxidation state. It has maximum polarising power. Hence, possess higher covalent character.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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