MHT CET · Chemistry · Amines
Which of the following conversions is Hofmann Elimination reaction?
- A \(\mathrm{RCONH}_2 \xrightarrow{\mathrm{Br}_2, \mathrm{KOH}_{(\mathrm{aq})}} \mathrm{R}-\mathrm{NH}_2\)
- B \(\mathrm{R}-\mathrm{NH}_2 \xrightarrow[\text { excess }]{\mathrm{R}-\mathrm{X}} \mathrm{R}_4 \mathrm{NX}\)
- C \(\mathrm{R}_4 \mathrm{NX} \xrightarrow[\Delta]{\text { moist } \mathrm{Ag}_2 \mathrm{O}}\) Alkene \(+\mathrm{R}_3 \mathrm{~N}\)
- D \(\mathrm{RCN} \xrightarrow{\mathrm{Na} / C_2 \mathrm{H}_5 \mathrm{OH}} \mathrm{RCH}_2 \mathrm{NH}_2\)
Answer & Solution
Correct Answer
(C) \(\mathrm{R}_4 \mathrm{NX} \xrightarrow[\Delta]{\text { moist } \mathrm{Ag}_2 \mathrm{O}}\) Alkene \(+\mathrm{R}_3 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
The Hofmann elimination reaction is a reaction in which a primary amide (RCONH2) undergoes elimination to form an amine and an alkene. This is typically done using excess aqueous potassium hydroxide \((\mathrm{KOH})\).
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