MHT CET · Chemistry · d and f Block Elements
Which gives \(+7\) oxidation state?
- A \(\mathrm{Mn}(25)\)
- B \(\mathrm{Cr}(24)\)
- C \(\operatorname{Cu}(29)\)
- D \(\mathrm{Fe}(26)\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Mn}(25)\)
Step-by-step Solution
Detailed explanation
For \(d\) -block elements, oxidation state \(=n s\) electrons \(+(n-1) d\)
electrons (unpaired)
(a) \(\operatorname{Mn}(25)=[\operatorname{Ar}] 3 d^{5} 4 s^{2}\)
\(
\text { O. } \mathrm{S} .=5+2=7
\)
(b) \(\operatorname{Cr}(24)=[\operatorname{Ar}] 3 d^{5} 4 s^{1}\)
O. S. \(=5+1=6\)
(c) \(\operatorname{Cu}(29)=[\mathrm{Ar}] 3 d^{10} 4 s^{1}\)
O. S. \(=0+1=1\)
(d) \(\mathrm{Fe}(26)=[\mathrm{Ar}] 3 d^{6} 4 s^{2}\)
O.S. \(=+2\) and \(+3\)
Thus, only Mn exhibits \(+7\) oxidation state among the given elements.
electrons (unpaired)
(a) \(\operatorname{Mn}(25)=[\operatorname{Ar}] 3 d^{5} 4 s^{2}\)
\(
\text { O. } \mathrm{S} .=5+2=7
\)
(b) \(\operatorname{Cr}(24)=[\operatorname{Ar}] 3 d^{5} 4 s^{1}\)
O. S. \(=5+1=6\)
(c) \(\operatorname{Cu}(29)=[\mathrm{Ar}] 3 d^{10} 4 s^{1}\)
O. S. \(=0+1=1\)
(d) \(\mathrm{Fe}(26)=[\mathrm{Ar}] 3 d^{6} 4 s^{2}\)
O.S. \(=+2\) and \(+3\)
Thus, only Mn exhibits \(+7\) oxidation state among the given elements.
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