MHT CET · Chemistry · Coordination Compounds
Which from the following statements about \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\) complex is NOT correct?
- A Prior to hybridization \(\mathrm{Co}^{3+}\) possesses four unpaired electrons.
- B This complex has all electrons'paired.
- C It is a high spin complex.
- D It is a diamagnetic complex.
Answer & Solution
Correct Answer
(C) It is a high spin complex.
Step-by-step Solution
Detailed explanation
In \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\), oxidation state of cobalt is +3 . Valence shell electronic configuration of \(\mathrm{Co}^{3+}\) is represented in box diagram as shown:

Thus, prior to hybridisation, \(\mathrm{Co}^{3+}\) possesses 4 unpaired electrons.
Complex is low spin, so pairing of electrons will take place and electronic configuration after pairing would be
Six orbitals available for hybridisation are two 3 d , one 4 s , three 4 p orbitals

As all electrons are paired, the complex is diamagnetic.

Thus, prior to hybridisation, \(\mathrm{Co}^{3+}\) possesses 4 unpaired electrons.
Complex is low spin, so pairing of electrons will take place and electronic configuration after pairing would be

Six orbitals available for hybridisation are two 3 d , one 4 s , three 4 p orbitals

As all electrons are paired, the complex is diamagnetic.
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