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MHT CET · Chemistry · Coordination Compounds

Which from following is a correct stability order of complex formed by metal ions if the ligand remains same?

  1. A \(\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\gt\mathrm{Co}^{2+}\)
  2. B \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\)
  3. C \(\mathrm{Co}^{2+}\gt\mathrm{Mn}^{2+}\gt\mathrm{Fe}^{2+}\)
  4. D \(\mathrm{Fe}^{2+}\gt\mathrm{Co}^{2+}\gt\mathrm{Mn}^{2+}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\)

Step-by-step Solution

Detailed explanation

The stability order of divalent metal ion complexes is given by Irving William series. Higher the charge to size ratio, greater is the stability of complex.
Hence, the order is \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\).