MHT CET · Chemistry · Coordination Compounds
Which from following is a correct stability order of complex formed by metal ions if the ligand remains same?
- A \(\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\gt\mathrm{Co}^{2+}\)
- B \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\)
- C \(\mathrm{Co}^{2+}\gt\mathrm{Mn}^{2+}\gt\mathrm{Fe}^{2+}\)
- D \(\mathrm{Fe}^{2+}\gt\mathrm{Co}^{2+}\gt\mathrm{Mn}^{2+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\)
Step-by-step Solution
Detailed explanation
The stability order of divalent metal ion complexes is given by Irving William series. Higher the charge to size ratio, greater is the stability of complex.
Hence, the order is \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\).
Hence, the order is \(\mathrm{Co}^{2+}\gt\mathrm{Fe}^{2+}\gt\mathrm{Mn}^{2+}\).
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